«
»

convert epoch using date command

date -d ‘<Unix epoch> <epoch date> sec’

e.g. date -d ’1970-01-01 988822888 sec’ would dated “Wed May 2 17:31:28 MYT 2001″

20080430 :

get a particular date in epoch, e.g. date -d ‘Apr 30 2008 00:00:00′ ‘+%s’

Related posts:

  1. Set time & date automatically in KDE For NTP use in KDE : - apt-get install ntpdate...
  2. Modify or Adjust File Date Time on Unix/Linux You have folders or files in your server last modified...
  3. Changing File’s Date and Time on Unix Systems Change Data and Time of a File At times, we...
  4. OS X Lion Release Date OS X Lion Release Date is Today, 20th July 2011...
  5. split – but no destination parameter to specify first : cd /destination/directory second : split /source/directory/big-huge-file prefix-to-apply-onto-splited-files Voila...
  6. How to dig SRV record after creating it in DNS dig <record type> <host.name> e.g dig SRV _someservice._port.hostname.domainame.com.my OR dig...
  7. ssh client hang after a few minutes of inactivity specify the parameter “ServerAliveInterval 60″ in /etc/ssh_config or /etc/ssh/ssh_config. for...
  8. ls & rm with regular expression e.g. rm -rf backup-20070[8-9]-* would delete : backup-200708-morning backup-200708-evening backup-200709-night...
  9. MySQL Cannot Connect with PHP in OSX I think some of you might have problem connecting to...
  10. TextMate: Creating New Project in Shell Instantly Been using TextMate recently, really loving it like hell. There...

Tags: , ,

This entry was posted on Sunday, April 13th, 2008 at 12:06 pm and is filed under Apple, Open Source, Systems. You can follow any responses to this entry through the RSS 2.0 feed. You can leave a response, or trackback from your own site.

3 Responses to “convert epoch using date command”

  1. Patric Says:
    July 14th, 2008 at 6:05 pm

    why not use the following?
    date -d ‘@’

    e.g. date -d @1216024547
    Mon Jul 14 10:35:47 CEST 2008

  2. suresh Says:
    November 18th, 2008 at 6:03 pm

    Hi,
    I trying to convert epoch seconds to D/M/Y H:M:S.s format. I am passing epoch seconds as an argument to perl file.
    Inside perl file, the code looks like this:

    my $epoch = $ARGV[0];
    open(OUT, “>c:/dateResultFile.txt”);
    my $str = “date -d ’1970-01-01 $epoch sec’” ;
    print OUT “$str\n”;
    close(OUT);

    when i executed this code, i am getting i am not getting the date as i expected.
    Please suggest me the solution.

  3. MB Says:
    July 31st, 2009 at 5:04 am

    $ date +%s -d”Jan 1, 1980 00:00:01″
    date: 0551-402 Invalid character in date/time specification.
    Usage: date [-u] [+"Field Descriptors"]

    System used is AIX…this doesn’t work

Leave a Reply