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convert epoch using date command

date -d ‘<Unix epoch> <epoch date> sec’

e.g. date -d ’1970-01-01 988822888 sec’ would dated “Wed May 2 17:31:28 MYT 2001″

20080430 :

get a particular date in epoch, e.g. date -d ‘Apr 30 2008 00:00:00′ ‘+%s’

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This entry was posted on Sunday, April 13th, 2008 at 12:06 pm and is filed under Apple, Open Source, Systems. You can follow any responses to this entry through the RSS 2.0 feed. You can leave a response, or trackback from your own site.

3 Responses to “convert epoch using date command”

  1. Patric Says:
    July 14th, 2008 at 6:05 pm

    why not use the following?
    date -d ‘@’

    e.g. date -d @1216024547
    Mon Jul 14 10:35:47 CEST 2008

  2. suresh Says:
    November 18th, 2008 at 6:03 pm

    Hi,
    I trying to convert epoch seconds to D/M/Y H:M:S.s format. I am passing epoch seconds as an argument to perl file.
    Inside perl file, the code looks like this:

    my $epoch = $ARGV[0];
    open(OUT, “>c:/dateResultFile.txt”);
    my $str = “date -d ’1970-01-01 $epoch sec’” ;
    print OUT “$str\n”;
    close(OUT);

    when i executed this code, i am getting i am not getting the date as i expected.
    Please suggest me the solution.

  3. MB Says:
    July 31st, 2009 at 5:04 am

    $ date +%s -d”Jan 1, 1980 00:00:01″
    date: 0551-402 Invalid character in date/time specification.
    Usage: date [-u] [+"Field Descriptors"]

    System used is AIX…this doesn’t work

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