Comments on: convert epoch using date command

By: MB

MB — Thu, 30 Jul 2009 21:04:08 +0000

$ date +%s -d”Jan 1, 1980 00:00:01″
date: 0551-402 Invalid character in date/time specification.
Usage: date [-u] [+"Field Descriptors"]

System used is AIX…this doesn’t work

By: suresh

suresh — Tue, 18 Nov 2008 10:03:06 +0000

Hi,
I trying to convert epoch seconds to D/M/Y H:M:S.s format. I am passing epoch seconds as an argument to perl file.
Inside perl file, the code looks like this:

my $epoch = $ARGV[0];
open(OUT, “>c:/dateResultFile.txt”);
my $str = “date -d ‘1970-01-01 $epoch sec’” ;
print OUT “$str\n”;
close(OUT);

when i executed this code, i am getting i am not getting the date as i expected.
Please suggest me the solution.

By: Patric

Patric — Mon, 14 Jul 2008 10:05:15 +0000

why not use the following?
date -d ‘@’

e.g. date -d @1216024547
Mon Jul 14 10:35:47 CEST 2008